View Code of Problem 58

#include<stdio.h>
#include<string.h>

int main(){
	char str[80];
	gets(str); //输入只有一行句子。仅有空格和英文字母构成。  ___qweqew____qwe___qwe__ 
	int i,flag,count;
	i = 0; flag = 0; count = 0;
	while(str[i]){
		//printf("1"); 
		if(str[i]==' ') flag = 0;
		else if('a'<=str[i]<='z'||'A'<=str[i]<='Z'){
			//printf("%c",str[i]); 
			if(!flag)
				count++;
			flag = 1;
		}
		//else{
		//	flag = 0;
		//}       
		i++;	
	}
	printf("%d",count);
	return 0 ;
}