View Code of Problem 72

#include<stdio.h>
int main()
{
	int n;double m,sum=0;
	scanf("%lf %d",&m,&n);
	for(int i=0;i<n;i++)
	{
		sum+=m;
		m/=2;
		sum+=m;	
	}
	sum-=m; 
	printf("%.2lf %.2lf",m,sum);
	return 0;
}