View Code of Problem 71

#include<stdio.h>
int main()
{
    int n,i,a=1,b=2,temp;
    double sum=0;
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {

        sum+=(double)b/a;
        temp=a;
        a=b;
        b=temp+b;
    }
    printf("%.2lf",sum);
    return 0;
}