View Code of Problem 72

#include<stdio.h>
#include<math.h>
int main()
{
	int n;
	double m,M;
	scanf("%lf%d",&m,&n);
    m=pow(0.5,n)*m;
	if(n==1)
		M=1000;
	else
		M=(3-pow(0.5,n-2))*1000;
	printf("%.2lf %.2lf",m,M);
	return 0;
}