View Code of Problem 48

#include<stdio.h> 
#include<math.h>
int main()
{
	int a[100];
	int i,n;
	double sum=0;
	a[0]=1;
	a[1]=2;
	scanf("%d",&n);
	for(i=2;i<n+1;i++)
	{
		a[i]=a[i-1]+a[i-2];
	}
	for(i=0;i<n;i++)
	{	
		sum+=(double)a[i+1]/a[i];
	}
	
	printf("%.6lf",sum);
	
}