View Code of Problem 72

#include<stdio.h>
#include<string.h>
int main()
{
     int n,i;
     double m,sum=0,x;
     scanf("%lf%d",&m,&n);
     x=m;
     for(i=1;i<=n;i++)
     {
         sum+=2*m;
         m=m/2;
     }
     printf("%.2lf %.2lf",m,sum-x);
     return 0;
    
}