View Code of Problem 70

#include<iostream>
using namespace std;
int main(void){
	double n,s;
	cin>>n;
	if(n<=100000)
		s=n*0.1;
	else if(n>100000&&n<=200000)
		s=10000+(n-100000)*0.075;
	else if(n>200000&&n<=400000)
		s=17500+(n-200000)*0.05;
	else if(n>400000&&n<=600000)
		s=27500+(n-400000)*0.03;
	else if(n>600000&&n<=1000000)
		s=33500+(n-600000)*0.015;
	else
		s=39500+(n-1000000)*0.01;
	printf("%.0lf",s);
}