View Code of Problem 72

#include<iostream>
using namespace std;
int main(void){
	double m,n,sum=0;
	cin>>m>>n;
	sum=m;
	for(int i=0;i<n;i++){
		m=m/2;
		sum+=m*2;
	}
	printf("%.2lf %.2lf",m,sum-m*2);
}