View Code of Problem 48

    #include<stdio.h>
    #include<math.h>
    int main()
    {
      int n,a[10];int i;
      a[0]=1;a[1]=2;
      double sum=0;
      scanf("%d",n);
      for(i=2;i<n;i++)
      {
        a[i]=a[i-1]+a[i-2];
      }
      for(i=0;i<n;i++)
      {
      sum+=(double)a[i+1]/a[i];
        printf("%.6lf",sum);
      }
      return 0;
    }