View Code of Problem 48

            #include<stdio.h>
            #include<math.h>
            int main()
            {
              int n,a[10];int i;
              a[0]=1;a[1]=2;
              double sum=0;
              scanf("%d",&n);
              for(i=2;i<=n;i++)
              {
                a[i]=a[i-1]+a[i-2];
              }
              for(i=0;i<n;i++)
              {
              sum+=(double)a[i+1]/a[i];
                printf("%.6lf",sum);
              }
              return 0;
            }