View Code of Problem 48

 #include<stdio.h>
        #include<math.h>
        int main()
        {
          int n,a[10];int i;
          a[0]=1;a[1]=2;
          double sum=0;
          scanf("%d",&n);
          for(i=2;i<n;i++)
          {
            a[i]=a[i-1]+a[i-2];
          }
          for(i=0;i<n;i++)
          {
          sum+=(double)a[i+1]/a[i];
            printf("%.6lf",sum);
          }
          return 0;
        }