View Code of Problem 88

#include <stdio.h>
#include <string.h>
#include <math.h>
#define N 10000
int main()
{
	int a[6];
	int n;
	int i;
	int count=0;
	int sum=0;
	for(i=0;i<6;i++)
		scanf("%d",&a[i]);
	count=a[5]+a[4]+a[3]+(a[2]+3)/4;
		printf("%d\n",count);
}