View Code of Problem 70

#include<stdio.h>
int main(){
    int n;
    long long sum,a=0;
    scanf("%lld",&sum);
    if(sum<=100000){
        n=1;
    }else if(sum>100000&&sum<=200000){
        n=2;
    }else if(sum>200000&&sum<=400000){
        n=3;
    }else if(sum>400000&&sum<=600000){
        n=4;
    }else if(sum>600000&&sum<=1000000){
        n=5;
    }else{
        n=6;
    }
    switch(n){
        case 6:a=a+(sum-1000000)*0.01;
        case 5:a=a+(sum-600000)*0.015;
        case 4:a=a+(sum-400000)*0.03;
        case 3:a=a+(sum-200000)*0.05;
        case 2:a=a+(sum-100000)*0.075;
        case 1:a=a+sum*0.1;break;
    }
    printf("%d\n",a);
    return 0;
}