View Code of Problem 48

#include <stdio.h>
int main( ){
	int n;
	scanf("%d",&n);
	int i;
	double sum=2;
	double t=2;
	double k=1;
	int m=0;
	double a[10];
	a[0]=1;
	a[1]=2;
	for(i=2;i<10;i++){
		a[i]=a[i-1]+a[i-2];
	}
	double b[10];
	b[0]=2;
	b[1]=3;
	for(i=2;i<10;i++){
		b[i]=b[i-1]+b[i-2];
	}
	for(i=1;i<n;i++){
		sum+=b[i]/a[i];
	}
	printf("%.6lf\n",sum);
	return 0;
}

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